A missle coliding witha satelite

  • Thread starter talolard
  • Start date
  • Tags Tags
    Satelite
5 replies · 2K views · last reply
talolard
Messages
119
Reaction score
0

Homework Statement




I typed it in word. Is this correct?
Thanks
Tal
Typed worked solution on a physics problem about a missile colliding with a satellite, showing equations for speeds, conservation of momentum and energy, and a final expression for r.
 
Attachments
  • Typed worked solution on a physics problem about a missile colliding with a satellite, showing conservation of momentum and energy equations with square roots and fractions, including V_new = sqrt(GmM/r + sqrt(GM R)) over 1.2 and a final expression for r.
    Phys Q.JPG
    36.3 KB · Views: 533
Isn't the satellite moving in a circular orbit and the missile in the radial direction? It seems to me that their velocities are perpendicular to each other which means you have a collision in two dimensions.
 
talolard said:
I agree but i don't see what that means.
It means that the sum of the two momentum vectors before the collision is equal to the single momentum vector after the collision. How do you two add vectors that are perpendicular to each other?
 
Standard vector addition?
I don't see how vectors are relevant though because all of my quantities are scalrs and not vectors.

I solved this problem correctly previously using conservation of energy but I don't understand why momentum is wrong.
 
talolard said:
Standard vector addition?
I don't see how vectors are relevant though because all of my quantities are scalrs and not vectors.
The initial momentum of the satellite is not in the same direction as the initial momentum of the missile. Therefore, to find the total initial momentum, you need to add the two as vectors. You need the total initial momentum to use in the momentum conservation equation.
I solved this problem correctly previously using conservation of energy but I don't understand why momentum is wrong.
It is correct to use energy conservation after the collision is completed, however the solution will not be correct unless the velocity of of the composite mass immediately after the collision is calculated correctly.