A more direct approach in determining moment of inertia?

AI Thread Summary
The discussion focuses on understanding the moment of inertia without delving into calculus, emphasizing the constant values for different shapes, such as 2/5 for a sphere and 1/2 for a cylinder. It highlights that the moment of inertia (I) decreases when mass is closer to the axis of rotation. While mnemonics are suggested for remembering these constants, the conversation concludes that there are no shortcuts or tricks involved. The parallel axis theorem is mentioned as a helpful tool for translating moment of inertia to a parallel axis. Overall, the thread aims to simplify the concept of moment of inertia for easier comprehension.
bluejay27
Messages
67
Reaction score
3
is there a directly knowing the moment if the moment of inertia would be lower for an object? I am emphasizing on knowing the value of the constant value. For a sphere is 2/5 and for a cylinder 1/2, this constant values will be placed at c of cMR^2 without directly going into calculus. A mnemonic perhaps?
 
Physics news on Phys.org
I take it you know the definition of ##I##, the moment of inertia ? The closer the massive stuff is to the axis, the lower ##I##. And that's about it. You can go through the list and conclude for yourself there's no tricks or mnemonics.
The parallel axis theorem can be useful to translate to another (parallel) axis.
 
  • Like
Likes bluejay27
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top