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## Homework Statement

On average, each of the 18 hens in my henhouse lays 1 egg every 30 days. If I check the hens once per day and remove any eggs that have been laid, what is the average number, μ, of eggs that I find on my daily visits? What is the most probable (whole) number of eggs that I find on each visit? HINT: if in doubt sketch the distribution of P(N) in this case.

## Homework Equations

[tex]P_{\mu}(N)=\frac{e^{-\mu}{\mu}N}{N!}[/tex]

## The Attempt at a Solution

18 hens lay 1 egg every 30 days so average, [tex]\mu[/tex], is 0.6 eggs a day.

Number of occurences, N, is 1 as it is checked once a day.

so P_[tex]\mu[/tex](N) = 0.329 using the numbers given.

And the most probable whole number of eggs found on each visit is 0.

Is this correct??