A positive charge of magnitude Q1 = 8.5 nC is located....

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SUMMARY

The discussion focuses on calculating the x-component of the electric field at point P due to a positive charge Q1 = 8.5 nC located at the origin and a negative charge Q2 = -8.5 nC positioned 16.5 cm along the positive x-axis. The electric field equation used is Efield = (K)(Q)/(r²), where K is the electrostatic constant. The user initially miscalculated the electric field by incorrectly applying the formula, leading to an incorrect result. After clarification, the user acknowledged the mistake and expressed gratitude for the assistance.

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Homework Statement


A positive charge of magnitude Q1 = 8.5 nC is located at the origin. A negative charge Q2 = -8.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 7.5 cm above charge Q2. Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Homework Equations



Efield = (K)(Q)/(r2)

The Attempt at a Solution


I found the E-field created by Q1 by doing (k)(Q1)/(r2). I found r to be .18125 by performing the Pythagorean Theorem on the x and y legs. I then multiplied this answer by x/r because it asks for just the x-component, which is the E-field times cos(θ), and cos(θ) is adjacent/hypotenuse. I got 421.506 for the E-field and .910345 for cos(θ), and after multiplying these, I got 383.716, which is not the right answer. Any help is much appreciated.
 
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brioches said:
I got 421.506
You seem to have used kq/r, not kq/r2.
 
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haruspex said:
You seem to have used kq/r, not kq/r2.
Welp, that was definitely it. Thanks so much!
 

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