A problem in polar i want check my answer

  • Thread starter r-soy
  • Start date
  • #1
r-soy
173
1
write in polar form ...elc
-3 - 5i

my answer :

x = -3 y = - 5

r = root (-3)^2 + (-5)^2
= 5.83

tan Q = 5/3 = -1.12
tan-1 -1.12 = -0.84
Q = -0.84
Q = -pi + -0.84 = -3.981

Polar form = 5.83e^(-3.981)i
 

Answers and Replies

  • #2
ammontgo
16
0
Ok first off:
I believe you've recorded your answer in exponential form.

Forms of Complex Numbers:

[PLAIN]https://dl.dropbox.com/u/4645835/MATH/ComplexForms.gif [Broken]

Please correct me if I'm wrong.
 
Last edited by a moderator:
  • #3
ammontgo
16
0
I think your angle may be wrong as well. This is what I did:

[PLAIN]https://dl.dropbox.com/u/4645835/MATH/Ex1.gif [Broken]

I can explain why I added 180 degrees to the angle I calculated - if needed.
 
Last edited by a moderator:
  • #4
r-soy
173
1
Hi

but as I know in this question we change calculator to ( Rad ) nor (deg) because we have integer number -3 and - 5 not roots or ,

and please I want explaine more because I don't understand clearly
 
  • #5
36,667
8,669
write in polar form ...elc
-3 - 5i

my answer :

x = -3 y = - 5

r = root (-3)^2 + (-5)^2
= 5.83

tan Q = 5/3 = -1.12
tan Q = 5/3, but 5/3 is not equal to -1.12
tan-1 -1.12 = -0.84
Q = -0.84
Q = -pi + -0.84 = -3.981

Polar form = 5.83e^(-3.981)i
 

Suggested for: A problem in polar i want check my answer

Replies
1
Views
276
Replies
4
Views
453
Replies
16
Views
235
Replies
10
Views
817
Replies
8
Views
475
Replies
7
Views
543
  • Last Post
Replies
17
Views
270
Replies
11
Views
235
Replies
1
Views
291
Replies
14
Views
456
Top