A problem on parametric vector form of the plane

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The discussion revolves around finding a vector equation of a plane based on given parametric equations. The equations provided are X = 1 + 2t1 - 3t2, y = 3 + 4t1 - 4t2, and z = 2 + 3t1 - 5t2. A participant clarifies that the vector equation format is \vec{r}(t_1,t_2) = x(t_1, t_2)\vec{i} + y(t_1, t_2)\vec{j} + z(t_1, t_2)\vec{k}. The final vector equation is presented as a matrix equation, indicating the solution to the problem.
Syeda_Nadia
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hi...

please help me this question.
i am not understand this question.

Find a vector equation of the plane for the following parametric equations:
X= 1 +2t1 – 3t2
y = 3 + 4t1 – 4t2
z = 2 + 3t1 – 5t2

i just want a solution, just let me know if possible.
 
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A "vector equation" for any surface, with parameters t_1 and t_2 is
\vec{r}(t_1,t_2)= x(t_1, t_2)\vec{i}+ y(t_1, t_2)\vec{j}+ z(t_1, t_2)\vec{k}


1) This looks like a homework problem.

2) Though it talks about "vector", this is not really a "Linear and Abstract Algebra" question.

I am moving it to the "Calculus and Beyond" homework section.
 
Last edited by a moderator:
Welcome to PF, Syeda_Nadia! :smile:

I believe your vector equation would be:
\begin{pmatrix}x\\y\\z\end{pmatrix} = \begin{pmatrix}1\\3\\2\end{pmatrix} + t_1 \begin{pmatrix}2\\4\\3\end{pmatrix} + t_2\begin{pmatrix}-3\\-4\\-5\end{pmatrix}
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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