- #36
vcsharp2003
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- 162
You mean the same translation motion for each point of the rigid body.And if the bodies in interest are rigid, a linear motion of the CoM implies the same linear motion for every point of the rigid bodies.
You mean the same translation motion for each point of the rigid body.And if the bodies in interest are rigid, a linear motion of the CoM implies the same linear motion for every point of the rigid bodies.
I am assuming that the disks are in a horizontal position due to the mentioned vertical axis in problem statement. I am hoping that was also your assumption.It is always valid to represent a motion as a sum of motions, and it often helps to represent a rotation about a point other than the CoM as a rotation about the CoM plus a linear motion of the CoM.
So, when determining angular momentum about it's center axis, the translation motion part will not contribute to the angular momentum, only rotational part will contribute to angular momentum. Is that right?And if the bodies in interest are rigid, a linear motion of the CoM implies the same linear motion for every point of the rigid bodies.
If it is floating in space there is no vertical or horizontal. The reference to a vertical axis is strange anyway since it had not stated the disks were horizontal. I feel it was just a clumsy way of trying to say an axis normal to the plane of the disks.I am assuming that the disks are in a horizontal position due to the mentioned vertical axis in problem statement. I am hoping that was also your assumption.
But, what you said in post#27 and 29 wouldn't change even if the disks were horizontally aligned?If it is floating in space there is no vertical or horizontal. The reference to a vertical axis is strange anyway since it had not stated the disks were horizontal. I feel it was just a clumsy way of trying to say an axis normal to the plane of the disks.
Based on the fact about translation motion plus rotational motion, I reached the following conclusion. The smaller disk is considered a point mass.It is always valid to represent a motion as a sum of motions, and it often helps to represent a rotation about a point other than the CoM as a rotation about the CoM plus a linear motion of the CoM.
Wow, you're a master in Google search. I spent many hours to search for original test paper and also it's solutions, but I couldn't get your results even after using your suggestion in an earlier post.As previously noted (Post #12) the question is from this exam paper:
https://www.fiitjeenorthwest.com/admin/upload/AITS-1819-OT-JEEA-PAPER-2_3-2-19.pdf
It wasn't too hard to find the official solutions. They are here:
https://fiitjeefaridabad.weebly.com/uploads/8/6/6/9/8669642/aits-1819-ot-jeea-paper-2-sol.pdf
Please see my final working based on your inputs in post #41. After @SteveForPhysics posted the solution link, I cross checked my answer with problem#13 in that solution sheet and it exactly matches. Wow, what an effort. This was after all a good problem and not an impossible problem.If it is floating in space there is no vertical or horizontal. The reference to a vertical axis is strange anyway since it had not stated the disks were horizontal. I feel it was just a clumsy way of trying to say an axis normal to the plane of the disks.
I Googled:Very few people will have your skills for Google search.
For some reason, I'm not getting the 4th listing as the match. I'll look more into this. I'm not getting anything like an answer sheet, but I'll keep searching.I Googled:
jee advanced 2019 paper 2 "03-02-2019" solutions
Not that clever, though I had to put the date in quotes as a refinement. The answer was the 4th match. Try it for yourself.