1. The problem statement, all variables and given/known data If ε = 10, give a value of δ that satisﬁes |δ - a| where a = 2 and 0 < δ ≤ 1 and also guarantees that|f(x) − 1/4|< ε where f(x) = 1/(x^2) 2. Relevant equations N/A 3. The attempt at a solution My problem is the solution. The solution is δ = min(1,8) = 1. I am assuming that ε begins at L = 1/4 because |f(x) - L| is usually implied. So I graphed it out; I can see that any position of 0 < δ ≤ 1 from position a works when ε = 10 and 0 < δ ≤ 1. But I have no idea how the answer gets min (1,8). Anything larger than x = 2 is outside of ε.