A problem with the convergence of a series

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SUMMARY

The discussion centers on the convergence of the series defined by the term an = ((2n+100)/(3n+1))^n. The user initially applies the root test (racine test) and concludes that the series converges since the limit approaches 2/3. However, confusion arises when evaluating the limit as n approaches infinity, which results in +infinity, contradicting the convergence condition that an must approach 0. The resolution comes from recognizing the need to include the denominator in the logarithmic evaluation.

PREREQUISITES
  • Understanding of series convergence tests, specifically the root test (racine test).
  • Familiarity with limits and their evaluation as n approaches infinity.
  • Knowledge of logarithmic functions and their properties in calculus.
  • Basic algebraic manipulation of sequences and series.
NEXT STEPS
  • Review the application of the root test in series convergence.
  • Study the properties of logarithms in limit evaluations.
  • Explore examples of sequences that converge and diverge to solidify understanding.
  • Learn about other convergence tests such as the ratio test and comparison test.
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Students studying calculus, particularly those focusing on series and sequences, as well as educators seeking to clarify convergence concepts in mathematical analysis.

Amaelle
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Homework Statement
Show that the following sequence is convergent
Relevant Equations
Racine test
Good day
I have a question about the convergence of the following serie
inf.png


I understand that the racine test shows that it an goes to 2/3 which makes it convergent
but I also know that for a sequence to be convergent the term an should goes to 0 but the lim(n---->inf) ((2n+100)/(3n+1))^n)=lim exp(n*log(2n+100)/(3n+1))=+infinity
I'm really confused
thank you!
 
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What do you get if you cancel the quotient by ##n## instead of taking the logarithm?
 
Amaelle said:
lim exp(n*log(2n+100)/(3n+1))=+infinity
You should rethink this part. Try plugging in a large value of ##n## and see if it's what you expect.
 
Amaelle said:
Homework Statement:: Show that the following sequence is convergent
Relevant Equations:: Racine test

Good day
I have a question about the convergence of the following serie
View attachment 283529

I understand that the racine test shows that it an goes to 2/3 which makes it convergent
but I also know that for a sequence to be convergent the term an should goes to 0 but the lim(n---->inf) ((2n+100)/(3n+1))^n)=lim exp(n*log(2n+100)/(3n+1))=+infinity
I'm really confused
thank you!
The denominator, 3n+1, is also inside the log.
 
vela said:
You should rethink this part. Try plugging in a large value of ##n## and see if it's what you expect.
thank you very much I just spotted the mistake!
 
FactChecker said:
The denominator, 3n+1, is also inside the log.
thank you it's clear now
 

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