A question from a test i had today

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SUMMARY

The discussion centers on solving the discrete math problem of finding three positive integers greater than 1 such that \(28 \equiv -27 \mod m\). The correct interpretation leads to the equation \(28 + 27 = 55\), which implies that \(m\) must be a divisor of 55. The valid divisors identified are 55, 11, and 5, confirming that these values satisfy the modular condition.

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Homework Statement


a question from a test in discrete math:
find 3 positive numbers that are larger than 1, that 28=-17(mod m)




Homework Equations


which is 28 + 17/m = t
so its 55/m = t
can i say that m= 55,11,5 because they devise 55?

thanks

The Attempt at a Solution


 
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Hi NightFire! :smile:

erm … 28 + 17 = 45 :redface:

otherwise ok! :biggrin:
 
tiny-tim said:
Hi NightFire! :smile:

erm … 28 + 17 = 45 :redface:

otherwise ok! :biggrin:

Oh sry my bad! it was -27 and not -17 lol, so yea: 28= -27(mod m)

Thanks! :)
 

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