?? No, A-1 doesn't mean anything like that: it means the linear operation that "undoes" A. A-1Ax= x and AA-1x= x.transgalactic said:it means that if we take the image of a certain basis
and put it into the A^-1 we get the original basis
My point was that A(I- A)= I shows that I -A does exactly what we want of the inverse: AA-1= I. Since A(I-A)= I, (and inverses are unique), A-1= I- A.how its going to help me??
thought of certain solution of making some basic multiplication
operations
i got the resolt
A^-1=I-A
is it ok??
An invert of an operator is a mathematical function that reverses the effects of the original operator. It is denoted as the reciprocal of the original operator and is used to undo the operation performed by the original operator.
Finding the invert of an operator is important because it allows us to solve equations involving the original operator. It also helps in simplifying complex mathematical problems and finding solutions to various scientific and engineering applications.
The process of finding the invert of an operator varies depending on the type of operator. In general, it involves finding the inverse function of the original operator, which is done by manipulating the equation in terms of the inverse function. This process can be complex and may require advanced mathematical techniques.
Some common examples of operators and their inverses include addition and subtraction, multiplication and division, logarithms and exponentiation, and differentiation and integration. In each case, the inverse function undoes the operation performed by the original operator.
Yes, there are limitations to finding the invert of an operator. In some cases, an operator may not have an inverse function, making it impossible to find its invert. Additionally, the process of finding the invert of an operator can be complex and may not always result in a simple solution.