An object of 6.0kg is whirled round in a vertical circle of radius 2.0m with a speed of 8.0m/s. If the string breaks when the tension in it exceeds 360N, calculate the maximum speed of rotation, and state where the object will be when the string breaks.
The usual circular motion equations
The Attempt at a Solution
I calculated the max speed to be over 10m/s when the object is at the top (tension force + weight force =centripetal force, hence greater centripetal force and therefore greater maximum speed of rotation), but my sources suggest that the speed is greatest when the tension exceeds 360N at the bottom (which is tension force - weight force =centripetal force, leading to a smaller centripetal force and hence less speed.)
I am needing assistance to clarify the situation. how is it that the linear speed at the bottom is greater than the top (as my teacher's notes state). Would the object have a greater linear speed and a greater speed of rotation at the top because the centripetal force is greater there?
I may have totally confused the physics...
Thanks in advance,