A question regarding power and hookes law

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SUMMARY

The discussion focuses on calculating the power required to compress a spring using Hooke's Law. Given a spring constant of 12 N/m and a compression of 1.2 m over 2.5 seconds, the potential energy (Pe) is calculated as 8.64 J using the formula Pe = 1/2 kx². The power is then determined by dividing the work done (8.64 J) by the time (2.5 s), resulting in a power output of 3.456 watts. The calculations are confirmed as correct by participants in the discussion.

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Homework Statement



A 2.8 m high spring has a spring constant of 12 N/m. How much power is required if the spring is compressed 1.2 m in 2.5s?

Homework Equations



Pe= 1/2kx^2

Power= W/t

The Attempt at a Solution



=1/2(12)(1.2)^2
=8.64 J

so... Power = 8.64/2.5

= 3.456 watts

is this correct? thanks in advance!
 
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