A question regarding Special Relativity.

Click For Summary

Discussion Overview

The discussion revolves around the implications of a rocket traveling at a constant speed of 0.9c while firing photons at regular intervals, and how observers on Earth perceive these photons. The participants explore the effects of relativistic time dilation and the challenges in determining the rocket's position, especially when considering acceleration.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the time between each photon being fired is affected by time dilation, resulting in a time of approximately 2.29416 seconds observed on Earth for each second of proper time on the rocket.
  • There is a suggestion that observers on Earth can only determine the positions of the rocket at the times the photons were emitted, not its current position.
  • One participant questions how to calculate the rocket's position if it is accelerating, noting that both \(\Delta t\) and \(\Delta \tau\) would change during acceleration.
  • Another participant confirms that the time observed on Earth for the photons will be longer than 2.29416 seconds due to the relativistic Doppler effect, providing a formula to calculate the Doppler factor for objects moving apart.
  • The same participant derives the Doppler factor for the rocket's speed and suggests that this could be used to track the change in position as the rocket accelerates.

Areas of Agreement / Disagreement

Participants generally agree that the observed time for the photons is affected by relativistic effects, but there is no consensus on how to accurately calculate the positions of the rocket during acceleration. Multiple competing views and methods are presented without resolution.

Contextual Notes

Participants express uncertainty regarding the calculations involved in determining the rocket's position during acceleration and the implications of changing time intervals on the measurements made by observers on Earth.

JPBenowitz
Messages
144
Reaction score
2
Suppose there is a rocket that is traveling at a constant .9c starting at an initial position x1 and fires a photon every second to observers on earth. (Observers on Earth do not know the velocity of the rocket)

If 1s is the proper time \Delta\tau then the time passed on Earth between each photon being fired would be \gamma or 2.29416s. Then dependent on the initial position x1 the time between each measured photon on Earth would be the time for each photon to travel the distance d from each position x at every 2.29416s? From measuring the time between each photon that reaches Earth you could calculate the positions x2...xn. But you would only be able to know the positions of where the rocket was not where it is presently.

Assuming I understand the above, how would someone go about by calculating the positions if the rocket is accelerating?
 
Physics news on Phys.org
JPBenowitz said:
Suppose there is a rocket that is traveling at a constant .9c starting at an initial position x1 and fires a photon every second to observers on earth. (Observers on Earth do not know the velocity of the rocket)

If 1s is the proper time \Delta\tau then the time passed on Earth between each photon being fired would be \gamma or 2.29416s. Then dependent on the initial position x1 the time between each measured photon on Earth would be the time for each photon to travel the distance d from each position x at every 2.29416s? From measuring the time between each photon that reaches Earth you could calculate the positions x2...xn. But you would only be able to know the positions of where the rocket was not where it is presently.

Assuming I understand the above, how would someone go about by calculating the positions if the rocket is accelerating?

Wait a minute, if the rocket is accelerating then \Deltat and \Delta\tau would be changing but the observers on Earth wouldn't be able to determine the relativistic time because it would be an element of the time it takes the photon to travel to earth.
 
JPBenowitz said:
But you would only be able to know the positions of where the rocket was not where it is presently.
Yes. That is always true.
 
JPBenowitz said:
Suppose there is a rocket that is traveling at a constant .9c starting at an initial position x1 and fires a photon every second to observers on earth. (Observers on Earth do not know the velocity of the rocket)

If 1s is the proper time \Delta\tau then the time passed on Earth between each photon being fired would be \gamma or 2.29416s. Then dependent on the initial position x1 the time between each measured photon on Earth would be the time for each photon to travel the distance d from each position x at every 2.29416s? From measuring the time between each photon that reaches Earth you could calculate the positions x2...xn. But you would only be able to know the positions of where the rocket was not where it is presently.

Assuming I understand the above, how would someone go about by calculating the positions if the rocket is accelerating?
You are right, the time observed from Earth of the 1 photon per second coming from the rocket will take even longer than the 2.29416 seconds. It's easy to calculate using the Relativistic Doppler Factor which for comparing intervals for objects moving directly apart from each other is:

D = √[(1+β)/(1-β)]

For β = 0.9
D = √[(1+0.9)/(1-0.9)]
D = √[(1.9)/(0.1)]
D = √19
D = 4.3589

That means as long as the rocket travels at the constant speed of 0.9c away from Earth and continues to send out a photon every second, Earth will receive them every 4.3589 seconds.

Now with a little algebra, you can turn the above formula around to calculate β if you know D:

β = |(1 - D2) / (1 + D2)|

So let's see if this works:

D = 4.3589
β = |(1 - D2) / (1 + D2)|
β = |(1 - 4.35892) / (1 + 4.35892)|
β = |(1 - 19) / (1 + 19)|
β = |-18/20|
β = |-0.9|
β = 0.9

So now we know how to determine the delayed speed of the rocket as it accelerates. If we wanted to keep track of the change in position just by looking at the Doppler Shift Periods, we could integrate the calculated speed measured as each photon was received.
 
Last edited:

Similar threads

  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K