A shell explodes into two identical fragments; find v

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SUMMARY

The discussion centers on a physics problem involving the conservation of momentum during an explosion of a shell into two identical fragments. The shell, with mass m and initial horizontal speed v, splits, with one fragment moving vertically at speed v. The correct approach requires treating momentum as a vector quantity and analyzing horizontal and vertical components separately. The initial misunderstanding stemmed from incorrectly adding momenta in different directions as scalars.

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Homework Statement


[/B]
A shell of mass m and speed v explodes into two identical fragments. If the shell was moving horizontally (the positive x direction) with respect to Earth, and one of the fragments is subsequently moving vertically with speed v, find the velocity v of the other fragment immediately following the explosion. (Use the following as necessary: v.)

Homework Equations



conservation of momentum: m1iv1i= 0.5m1fv1f+0.5m2fv2f

The Attempt at a Solution



So, what I did was set mv=.5mv+.5mv. Solving for v, I get v=v. I don't know what I'm doing wrong here. I'm pretty sure I'm supposed to be using the conservation of momentum equation, but I don't know where I'm going wrong. Thanks in advance for any help!
 
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toboldlygo said:
set mv=.5mv+.5mv.
Velocity and momentum are vectors. Your notation is very unclear, but it seems to me that on the right there you are adding momenta in two different directions as though they are scalars.
Consider horizontal and vertical momentum separately.
 
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haruspex said:
Velocity and momentum are vectors. Your notation is very unclear, but it seems to me that on the right there you are adding momenta in two different directions as though they are scalars.
Consider horizontal and vertical momentum separately.

Oh wow, that simplifies things so much. Thank you! Even though I've been using vectors for well over five weeks now I completely forgot.
 

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