- #1

Shivam

- 32

- 2

- Homework Statement
- A smooth massless wedge is pushed by a horizontal Force P, then

(1) If P=0, than N<mgcos(theta); N=Normal reaction received by block

(2) If P>0, than N=mgcos(theta)

(3) If a=0, than N=mgcos(theta);a=acceleration of the wedge

(4)If P=mgtan(theta), than N=mg/cos(theta)

- Relevant Equations
- F=ma, Cpmponents of weight

Answers- 1,3,4

My attempt, the wedge being massless, there shoul not be any force acting on as it will then have infinite acceleration, so by that i really can't think of how force is applied on pully.