A solved problem from Griffiths creats problem

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The discussion focuses on the vector potential of an infinite solenoid with n turns per unit length, radius R, and current I, as described in Griffiths' work. It emphasizes the application of Ampere's law, specifically the integral form correlating the closed integral of A.dl to the surface integral of B.da. The magnetic field B is defined as (μ)nI, resulting in a uniform axial field, while the vector potential A is circumferential. The analogy drawn by Griffiths between the solenoid and a fat wire carrying uniformly distributed current is critically examined, prompting further exploration of the justification for this analogy.

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Kolahal Bhattacharya
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A solved problem from Griffiths creats problem.It requires some discussion...It asks to find vector potential of an infinite solenoid with n turns per unit length radius R and current I.
Griffiths correlates integral form of Ampere's law to [closed integral of A.dl=surface integarl B.da].I can find A from this, with B=(mu)nI,uniform axial field and A circumferential.
But Griffiths says something here which I cannot understand.Quoting him,"The present problem (with a uniform magnetic field (mu)nI inside the solenoid and no field outside) is analogous to the Ampere's law problem of a fat wire carrying a uniformly distributed current.The vector potential is 'circumferential' (it mimics the magnetic field of the wire)."
As it appears, Griffiths is talking about the case where a fat wire is carrying a line current.In this case, magnetiv field is circumferential...But what is its justification?
 
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Try solving the problem for starts. What's the magnetic field for such a wire? Hint: you can still use Ampere's law for it.

Also, it would be very helpful if you took at look at https://www.physicsforums.com/showthread.php?t=8997 It makes reading posts with math infinitely easier, and if you're going to be a physicist, you're going to have to learn LaTeX sooner or later, anyway.
 

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