A Square Loop of Wire falling through a Magnetic Field

[TFM]

A good link, Thanks

so for the velocity:

1.67v = mg

$$v = \frac{mg}{1.67}$$

$$m = vol*\rho$$

$$v = \frac{vol \rho g}{1.67}$$

the volume is:

$$4*(length of side*area) = 4(0.1*\pi * 0.0005^2) = \pi * 10^{-6}$$

$$v = \frac{\pi * 10^{-6} (8960) (9.8)}{1.67}$$

this gives v to be: 0.165 m/s

Seems rather small?

 

[chrisk]

Your answer is correct. 1.2 Tesla is a HUGE B field and the mass of the wire is very small.

 

[TFM]

1.2 T is a large field, so I suppose the speed would be slow.

Thanks for all your assistance, chrisk, most appreciated

Thanks

TFM