A steel shuttle is pulled along a rail, what is its initial acceleration?

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SUMMARY

The initial acceleration of a 760g steel shuttle pulled by a 25N tension at a 45-degree angle is calculated using the formula F/m = a. The initial calculation yielded an acceleration of 32.89 m/s², but this did not account for friction. Considering the coefficient of friction for steel on steel (0.8), the correct formula becomes 25cos(45) - 0.8 * 0.76 * 9.8, leading to a more accurate acceleration value. Friction plays a crucial role in determining the actual acceleration of the shuttle.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of tension forces in physics
  • Familiarity with friction coefficients, specifically for steel on steel
  • Basic trigonometry, particularly cosine functions
NEXT STEPS
  • Study the effects of friction on motion in physics
  • Learn about tension forces and their applications in mechanics
  • Explore the concept of significant figures in scientific calculations
  • Investigate the role of angles in vector decomposition
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for practical examples of tension and friction in motion problems.

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Homework Statement
Question: a machine has a 760g steel shuttle that is pulled along a square steel rail by an elastic cord. the shuttle is released when the cord has a 25N tension at a 45-degree angle what is initial acceleration?
Relevant Equations
F = ma or F/m = a
it sounds like you just need to use F/m = a which gives 25 / .76 = 32.89 = a
this didn't work so I tried to get the x component of acceleration so I did 32.89cos(45) = 23.26 and this didn't work.

what am I missing, the force is tension right so it should be 25N?
 
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potatotimer said:
Homework Statement:: Question: a machine has a 760g steel shuttle that is pulled along a square steel rail by an elastic cord. the shuttle is released when the cord has a 25N tension at a 45-degree angle what is initial acceleration?
Relevant Equations:: F = ma or F/m = a

it sounds like you just need to use F/m = a which gives 25 / .76 = 32.89 = a
this didn't work so I tried to get the x component of acceleration so I did 32.89cos(45) = 23.26 and this didn't work.

what am I missing, the force is tension right so it should be 25N?
Two possibilities come to mind. First, have you rounded to an appropriate number of significant figures? Second, have you been studying friction and, if so, would the friction of steel on steel come into play?
 
jbriggs444 said:
Two possibilities come to mind. First, have you rounded to an appropriate number of significant figures? Second, have you been studying friction and, if so, would the friction of steel on steel come into play?
yeah its friction
rereading made me realize that friction does need to be considered which for a steel on steel collision u = 0.8
so the acceleration is 25cos(45) - .8*.76*9.8
thanks for the help :)
 
potatotimer said:
- .8*.76*9.8
Two errors in there.
 

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