A Trigonometric Identity Probelm

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Homework Help Overview

The discussion revolves around a trigonometric identity problem, specifically involving the manipulation of the identities related to sine and cosine functions. Participants are exploring the application of these identities to expressions involving sin²(2x) and cos²(2x).

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply known trigonometric identities to simplify expressions involving sin²(2x) and cos²(2x). Some participants question the validity of the transformations proposed, particularly regarding the sum of sin²(2x) and cos²(2x).

Discussion Status

Participants are actively discussing the application of trigonometric identities, with some providing clarifications on the correct relationships. There is a recognition of differing interpretations regarding the sum of sin²(2x) and cos²(2x), with guidance offered on the correct identity.

Contextual Notes

There is an emphasis on the validity of trigonometric identities across all real numbers, and the discussion highlights the importance of maintaining consistent angles in the identities used.

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[SOLVED] A Trigonometric Identity Probelm

If I have [tex]sin^2 2x[/tex] would I be able to apply the identity [tex]sin^2x = (1/2)(1-cos2x)[/tex] to get this:

[tex]sin^2 2x = 2(1/2)(1 - cos^2 x)[/tex]

Similarly, if I had [tex]sin^2 2x + cos^2 2x[/tex] would I be able to use the identity [tex]sin^2 x + cos^2 x = 1[/tex] to get:

[tex]sin^2 2x + cos^2 2x = 2[/tex]
 
Last edited:
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So in your case theta = 2x
sin^2(2x)= 1/2(1-cos(4x))
 
Last edited:
For the second half of your question, sin^2(2x) + cos^2(2x) = 1 (NOT 2)

Think about it, sin^2(x) + cos^2(x) = 1 for every value of x. So the range for x is (-infinity, +infinity). And of course 2x falls in that range (every real # falls in that range)
This applies as long as the angles are the same for both sin^2 and cos^2.
 
That explains a lot. I appreciate it, thank you.
 

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