A variational problem with the constraint that the function be decreasing

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Homework Help Overview

The discussion revolves around a variational problem involving a decreasing function defined on a specific set. The problem includes a constant parameter, $\theta$, and seeks to maximize a function $L$ defined in terms of integrals involving this function and a variable $h$. Participants are exploring the implications of the constraints on the function and the nature of the problem.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the definitions and constraints of the set $S$ and the function $L$. There are questions regarding the implications of the decreasing nature of the function $F$ and how it affects the maximization of $L$. Some participants also raise questions about the specific values of $\theta$ and their impact on the problem.

Discussion Status

The discussion is ongoing, with participants providing mathematical formulations and questioning the setup of the problem. There is an emphasis on understanding the constraints and the nature of the function involved, but no consensus has been reached on specific approaches or solutions.

Contextual Notes

Participants note the importance of correctly formatting mathematical expressions for clarity in the forum. There is also a mention of the specific range for $\theta$ and its relevance to the problem being discussed.

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The mathematical problem:

$\theta$ is a constant that equals 0.8.

We consider the set

'$ S=\left\{(F,h):F is a decreasing function from R^{+} to R^{+}, h\in R, 0=1- \frac{\theta+1)}{\theta} \frac {(\int^{h}_{y=0} F(y) dy)}{/F(0)} \frac{F(0)-\frac{1}{2}}{F(0)-F(h)} \right\}$'
The function L is defined on S by
$ L(F,h)= \frac{\int^{h}_{x=0} \int^{h}_{y=x} F(y) dy dx} {\int^{h}_{x=0} \int^{h}_{y=0} F(y) dy dx} h$
We want to find the maximal value of L.

A further problem:
Denote by $L(\theta)$ the maximal value of L. What is $max_{\theta \in (0,1)} \frac {L(\theta)}{\theta}$ ?
 
Last edited:
Lennart Stern said:
The mathematical problem:

$\theta$ is a constant that equals 0.8.

We consider the set

'$ S=\left\{(F,h):F is a decreasing function from R^{+} to R^{+}, h\in R, 0=1- \frac{\theta+1)}{\theta} \frac {(\int^{h}_{y=0} F(y) dy)}{/F(0)} \frac{F(0)-\frac{1}{2}}{F(0)-F(h)} \right\}$'
The function L is defined on S by
$ L(F,h)= \frac{\int^{h}_{x=0} \int^{h}_{y=x} F(y) dy dx} {\int^{h}_{x=0} \int^{h}_{y=0} F(y) dy dx} h$
We want to find the maximal value of L.

A further problem:
Denote by $L(\theta)$ the maximal value of L. What is $max_{\theta \in (0,1)} \frac {L(\theta)}{\theta}$ ?

If you want LaTeX to be readable in this forum, you need to remove the $ delimiters and enclose your commands between "[tex ]" and "[/tex ]" delimiters (no space after the word tex--I used a space so as to not confuse the system). For example, here is one of your formulas (justa copied and pasted between the delimiters I:
[tex]L(F,h)= \frac{\int^{h}_{x=0} \int^{h}_{y=x} F(y) dy dx} {\int^{h}_{x=0} \int^{h}_{y=0} F(y) dy dx} h[/tex]

RGV
 
[tex]\theta[/tex] is a positive constant.

We consider the set

[tex]S=\left\{(F,h):F is a decreasing function from R^{+} to R^{+}, h\in R, 0=1- \frac{\theta+1}{\theta} \frac {\int^{h}_{y=0} F(y) dy}{F(0)} \frac{F(0)-\frac{1}{2}F(h)}{F(0)-F(h)} \right\}[/tex]
The function L is defined on S by
[tex]L(F,h)= \frac{\int^{h}_{x=0} \int^{h}_{y=x} F(y) dy dx} {\int^{h}_{x=0} \int^{h}_{y=0} F(y) dy dx} h[/tex]
We want to find the maximal value of L, denoted by [tex]L(\theta)[/tex].

A special question:
What is L(0.8) ?

A general question:
What is [tex]max_{\theta \in (0,1)} \frac {L(\theta)}{\theta}[/tex] ?
 

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