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## Homework Statement

Steam initially at 120

^{o}C is passed into 0.60 kg of water initially at 20

^{o}C, and the total mass of water is just brought to the boil at 100C

What is the mass of steam that has condensed? Ignore the thermal capacity of the container and heat losses.

## Homework Equations

Q = cm(T2-T1) heat = specific heat * mass * change in temperature

Q = Lm heat = heat of Vaporisation or Fusion * mass

Heat of vaporisation of water is 2260 kJ/kg

Specific heat of water is 4200 J/kg.

^{o}C

Specific heat of steam is 2100 J/kg.

^{o}C

## The Attempt at a Solution

Qgained by water being heated = Qlost by steam being cooled + Q Lost by steam being condensed

cm

_{w}(T2-T1) = cm

_{stot}(T2-T1) +Lm

_{scondensed}

Unfortunately I can't seem to get rid of m

_{stot}. It is not given and I need to either work it out or find another equation. Help!

If it helps, the final answer should be 87g