Abstract Linear Algebra, Linear Functional

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SUMMARY

The discussion focuses on defining a non-zero linear functional T on the vector space C^3, specifically ensuring that T((1, 1, 1)) = T((1, 1, -1)) = 0. The user initially struggles with the definition of T and realizes that since both input vectors yield a zero output, a different approach is necessary. The solution involves expressing T((x,y,z)) in terms of its action on the basis vectors and selecting appropriate values for T((1,0,0)), T((0,1,0)), and T((0,0,1)) to satisfy the conditions.

PREREQUISITES
  • Understanding of vector spaces, specifically C^3.
  • Knowledge of linear functionals and their properties.
  • Familiarity with linear combinations and basis vectors.
  • Basic concepts of linear algebra, including the definition of zero vectors.
NEXT STEPS
  • Study the properties of linear functionals in vector spaces.
  • Learn how to construct linear functionals using basis vectors in C^n.
  • Explore examples of non-zero linear functionals in various vector spaces.
  • Investigate the implications of linear independence in defining functionals.
USEFUL FOR

Students of linear algebra, mathematicians, and educators seeking to deepen their understanding of linear functionals and their applications in vector spaces.

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Homework Statement


problem didn't state, but I assume let V be a vector space: V = C^3 and scalar is C


Homework Equations


Define a non-zero linear functional T on C^3 such that T ((1, 1, 1)) = T ((1, 1, −1)) = 0


The Attempt at a Solution


So let X1 = (1, 1, 1); X2 = (1, 1, -1);
It asks me to define a non zero linear functional, that means I need to define T(x) = α1T(x1) + α2T(X2) ?
Since T(X1) = T(X2) = 0 then T(X) = 0 then it's not the answer.
I'm stuck here. Can anyone give me a hint please? Thanks!
 
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T((x,y,z))=T((x,0,0))+T((0,y,0))+T((0,0,z))=x*T((1,0,0))+y*T((0,1,0))+z*T((0,0,1)). Because it's a linear functional, yes? Now you just need to pick values for T((1,0,0)), T((0,1,0)) and T((0,0,1)) that give the same value of 0 for your input vectors. Many choices are possible, just pick one.
 

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