AC circuit: Find the current through the inductor & capacitor

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SUMMARY

The forum discussion centers on calculating the current through an inductor and capacitor in an AC circuit using nodal analysis. User Michael_0039 presented their calculations, which were confirmed by another participant who also used nodal analysis, yielding consistent results. The correct value for the current I1 was identified as 3.4955 ∠ -11.2195°, although a mistake was noted in the evaluation of I1 at the end of Michael_0039's work. This error did not impact the results for the currents through the inductor (I(L)) and capacitor (I(C)).

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Michael_0039
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Homework Statement
AC circuit: Find the current through the inductor & capacitor
Relevant Equations
nil
Hi!

I wonder if it is correct. Can someone confirm (maybe with a software) ?

New Doc 2019-11-10 17.34.03_3.jpg


New Doc 2019-11-10 17.34.03_1.jpg


New Doc 2019-11-10 17.34.03_2.jpg


I(L) = I2
I(C) = I2 - I3
--

Thanks.
 
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Your work looks good. I worked the problem via nodal analysis and obtained the same results. Good job.
 
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Michael_0039, at the very end of your work, you didn't evaluate the expression for I1 correctly.

The correct value for I1 is 3.4955 ∠ -11.2195°

This doesn't affect your result for I(L) and I(C), but it is still a mistake.
 
The Electrician said:
Michael_0039, at the very end of your work, you didn't evaluate the expression for I1 correctly.

The correct value for I1 is 3.4955 ∠ -11.2195°

This doesn't affect your result for I(L) and I(C), but it is still a mistake.
You are right, I forgot (10+(10*I2))/12
 

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