AC Circuit Qs: Power & Current w/ 200V RMS

AI Thread Summary
An AC source of 200 V RMS supplies 600 W of active power and 800 VAR of reactive power, leading to a calculated rms current of 3.75 A, contrary to the incorrect value of 5 A initially derived. The user attempted to calculate current using the formula involving the sum of squared powers but misapplied the concept. A suggestion was made to consider a resistive and reactive load in series, leading to the correct calculation of impedance. The discussion also touched on the confusion surrounding the square root of 3 factor, which is relevant in three-phase systems but not applicable here. Ultimately, the correct approach clarified the misunderstanding and confirmed the accurate current value.
dhruv.tara
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Now this is not a homework question, just a practise question and my answer doesn't match.

An AC source of 200 V rms supplies active power of 600 W and reactive power of 800 VAR. The rms current drawn from the source is ? (the answer is 3.75 while mine is 5)

I did was squared and added the powers to get V^2*I^2, plugged in the value of V and got I as 5... Any help?
 
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I like your answer.

Try it with 24 ohms resistive and 32 ohms reactive in series.
I squared R:
5 * 5 * 24 = 600 watts
I squared X
5 * 5 * 32 = 800 VAR

resultant of r + x:
SQ rt of (24 * 24 + 32 * 32) = 40 ohms
200 V / 40 ohms = 5 amps
 
Last edited:
p=sqrt(3)*V*I*p.f
 
from where did that sqrt(3) factor come into? I have seen this factor before, but as far as I remember that was in 3 phase systems... And I am not dealing with such problem yet I think...
 
sorry, my mistake, you're right dump the sqrt(3).
 
hmm okiess... thanks all
 
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