AC Circuit using circuit parameters - HELP

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SUMMARY

The discussion focuses on solving AC circuit parameters, specifically calculating voltage Vab, active power dissipated in resistors, reactive power in inductors, and total current. The user employs formulas such as Vab = Va - Vb and I1 = (V∠0)/(2R) to derive circuit values. Key calculations include power dissipated in resistors using P = I²R and reactive power Q = I²jXl. The user expresses confusion regarding the total current calculation despite previous efforts.

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Sirsh
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Hey guys, Just need some help with this question, It asks for the answers to be in circuit parameters:
http://tinypic.com/r/k0k2ed/5
For some reason I don't think my answers are correct as I'm finding it hard to make sense of my answers to the questions.
a)Find the voltage Vab (magnitude and angle)
Vab = Va-Vb
current going to the first two resistors: I1=(V\angle0)/(2R)
current going through resistor and inductor: I2 = (V\angle0)/(R+Xl\angle90)
Itotal = I1+I2 = (V\angle0(3R+Xl\angle90))/(3R+2RXl\angle90)

Va=It*2R = (V\angle0(3R+Xl\angle90))/(3R+2RXl\angle90)*2R = (V\angle0(3R+Xl\angle90))/(R+2RXl\angle90)

Vb = It*(R+Xl\angle90) = (V\angle0(3R+Xl\angle90))/(3R+RXl\angle90)

Vab = Va-Vb
Therefore: (V\angle0(3R+Xl\angle90))/(R+2RXl\angle90) - (V\angle0(3R+Xl\angle90))/(3R+RXl\angle90).

Not sure if that's right.. A little insight would be appreciated!

b) Calculate the active power dissipated in each reistance.

Power dissipated in resitor/s (R) = I^2*R = ((V\angle0(3R+Xl\angle90))/(3R+2RXl\angle90))^2*R

Power dissipated in inductor = 0.

c) Calculate the reactive power dissipated in Xl.

Q = I^2*jXl = I^2*Xl\angle90 = ((V\angle0(3R+Xl\angle90))/(3R+2RXl\angle90))^2*Xl\angle90

d) calculate the total current
Now this is where I am confused it asks me to calculate the total current now even though i thought I already have.. Is this wrong?

Thanks a lot guys.
 
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Is there a schematic to accompany this?
 

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