AC Voltage and current, amplitude, rms, peak value

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SUMMARY

The discussion clarifies the relationship between AC voltage amplitude and peak voltage, confirming that voltage amplitude represents the maximum deviation from the DC value, or half the peak-to-peak value. It emphasizes the use of RMS current in Ohm's Law equations, while noting that peak values are often more convenient for sinusoidal or complex expressions. The conversation also highlights that AC voltage and current values are typically given as RMS by convention, with peak values being necessary for specific applications such as dielectric strength and nonlinear components. Relevant equations include V(odc) = 2 x Vmax / π and V(peak) = Vrms x √2.

PREREQUISITES
  • Understanding of AC voltage and current concepts
  • Familiarity with RMS and peak values in electrical engineering
  • Knowledge of Ohm's Law and its application
  • Basic grasp of waveform analysis and average value calculations
NEXT STEPS
  • Study the derivation and application of V(odc) = 2 x Vmax / π
  • Learn about the significance of peak versus RMS values in power calculations
  • Explore the effects of nonlinear components on AC waveforms
  • Investigate the role of peak values in dielectric strength specifications
USEFUL FOR

Electrical engineers, students in electrical engineering courses, and professionals involved in AC circuit analysis and waveform interpretation will benefit from this discussion.

Deathfish
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General enquiries (template may not be suitable)

- When the question provides value of AC voltage amplitude, is this the same value of peak voltage?

- Also, in current waveform, when do we use peak current and rms current?

- In ohm's law equations we use rms current, so in the current waveform graph do we need to times square root of 2?

- If provided with current waveform, can we get output dc current from using the same equation for voltage? eg. 2 x Vmax / \pi, Vmax / \pi

Relevant Equations :

V (odc) = 2 x Vmax / \pi, V(odc) = Vmax / \pi,
V (peak) = Vrms x \sqrt{2}
 
Last edited:
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Deathfish said:
General enquiries (template may not be suitable)

- When the question provides value of AC voltage amplitude, is this the same value of peak voltage?
yes, voltage amplitude means maximum deviation from DC value, or half the peak-to-peak
Deathfish said:
- Also, in current waveform, when do we use peak current and rms current?
there isn't a set rule for this unfortunately, in my electrical engineering course it is much easier to use peak values for sinusoidal or complex expressions. only cases I have come across using RMS is calculation of power dissapation
Deathfish said:
- In ohm's law equations we use rms current, so in the waveform graph do we need to times square root of 2?
as long as you are consistent, ie use only rms or only peak values in your calculatoins, ohm's law will hold, just like converting all units to metric units
Deathfish said:
- If provided with current waveform, can we get output dc current from using the same equation for voltage? eg. 2 x Vmax / \pi, Vmax / \pi
i'm not sure what these voltage formalae are used for but to obtain DC current you can use the ac waveform and find its average value over one cycle, more often then not they are quite obvious from inspection
 
Unless otherwise specified, AC voltage and current values are given as RMS. This is convention.

Sometimes it is necessary to know about peak values when specifying things like dielectric strengths or insulation. Also, if nonlinear components are involved (like diodes) and time constants or triggering levels are involved, you may need to work with the actual voltage or current waveforms in their 'peak' form.
 

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