Acceleration and Free Fall Problem

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A rocket accelerates vertically at 20.0 m/s² for 2 seconds before running out of fuel, transitioning to free fall. To find the maximum altitude, calculate the height at the end of powered flight using the equation X = Xo + Vot + (1/2)at², where the initial velocity (Vo) is determined by V = Vo + at. After fuel depletion, the rocket's ascent continues until it reaches its peak, where its velocity becomes zero. The maximum altitude is the sum of the height at fuel exhaustion and the additional height gained during free fall. The problem is analogous to projectile motion, where the initial conditions at fuel cutoff dictate the subsequent free fall trajectory.
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Homework Statement


A rocket is fired vertically and ascends with a constant vertical acceleration of 20.0 m/s^2 for 2.00 seconds. Its fuel is then used up and it continues as a free object. What is the maximum altitude reached?


Homework Equations


X=Xo+Vot+(1/2)at^2
V=Vo+at
2a(X-Xo)=V^2-Vo^2


The Attempt at a Solution


I usually start off making an x vs. t, v vs. t, and an a vs. graph in order to get a variable list so I can plug into the equation and solve but I'm thrown off by how to even begin the problem when it says it runs out of fuel and continues as a free object.
 
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At the end of the powered flight it becomes a free falling projectile (like a cannon ball in the normal questions) you just need to work out the starting velocity and height at the point the fuel runs out.

ps. Don't forget to add this start height to your answer for the free fall part of the flight.
 
Is the height of the point the fuel runs out the maximum height reached?
 
No
Consider the point the fuel runs out. Then it is exactly the same as throwing/firing an object upwards with a certain speed from that point.

Then all the same 'a cannon ball is fired with a speed ...' questions you have probably already done - apply.
 
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