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Acceleration, Displacement, Graph Interpretation

  • #1
lthcn99
Hello, I was working on a worksheet. It gave a graph that was velocity vs. time. I was asked to find the acceleration rate for the given (specific) time in seconds. My first question is if the line on the graph for example is from 1-3 seconds, in that 1-3 second range, is acceleration constant? And is it possible to have a negative acceleration? After finding the acceleration, I was asked to find the Normal Force using those acceleration and a person who weights 65 kg. Do I just use F=ma? Then I was asked to find I guess the displacement from 0-8 seconds. Do I make triangles, find area, and add them all up? Then lastly it asked if a elevator was 500 kg, what would be the tension pulling it. I'm hoping someone can help. Thank you.
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Answers and Replies

  • #2
Ray Vickson
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Hello, I was working on a worksheet. It gave a graph that was velocity vs. time. I was asked to find the acceleration rate for the given (specific) time in seconds. My first question is if the line on the graph for example is from 1-3 seconds, in that 1-3 second range, is acceleration constant? And is it possible to have a negative acceleration? After finding the acceleration, I was asked to find the Normal Force using those acceleration and a person who weights 65 kg. Do I just use F=ma? Then I was asked to find I guess the displacement from 0-8 seconds. Do I make triangles, find area, and add them all up? Then lastly it asked if a elevator was 500 kg, what would be the tension pulling it. I'm hoping someone can help. Thank you.
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  • #3
lthcn99
It ask me what would be the acceleration rate for 1 seconds. So I did A=vf-vi/t and got 4 m/s2 because y=8 and x=2 secs. But then it asks for the acceleration rate for 1.5 seconds, so will it still be 4 m/s2 cause it is constant? Then it ask for the acceleration rate for 6.5 seconds. I wasn't sure what to do so I did -8/6 and got -1.33 m/s2.
Part B ask what would be the normal force with a person of 65 kg. I'm confuse whether to use f=ma or N=f-mg. Like am I using the acceleration from above to solve this? I used f=ma, 65 x 4 = 260 N. 65 x -1.33 = -86.45 N.
For finding displacement, I went to find the areas of triangles from the graph. From 0-2 seconds is one triangle, so 1/2(b)(h), 1/2(2)(8)=8m. Then 3-4 seconds, I got 4 m. So I'm assuming from 0-4 secs, the displacement is 12m.
 
  • #4
scottdave
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Do you know what acceleration represents? What happens to velocity during time periods when acceleration is zero? What would the velocity graph look like during those time periods? You asked if negative acceleration is possible. The answer is yes. Try to think of examples of when acceleration is negative. Think about when you are driving or riding in a car. What horizontal accelerations act on you. When are the positive? When negative? When is acceleration zero?
 
  • #5
TiredCollegeStudent
Then lastly it asked if a elevator was 500 kg, what would be the tension pulling it.
Hint: Tension is a Force. Find out what is 500kg and how would it be related in finding the tension pulling it upwards.
 

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