(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

vehicle 1 is traveling at a constant speed of 90mph (132 f/s) 5 seconds before vehicle 2 begins to accelerate from 0-90 mph taking 17.09 seconds to do so. how far a distance will vehicle 2 travel while accelerating to 90mph. and how long will it take for vehicle 2 to catch up to vehicle 1 while accelerating at approximately 5.2 m/s/s or 15.6 f/s

2. Relevant equations

The relationship between the 2 vehicles is dependant.

what is the total distance traveled by vehicle 2 before it catches up to vehicle 1?

3. The attempt at a solution

ok, it's too hard to explain and argue at the same time, so i'll leave it at this:

find a function of position for car #1 and car #2, call them c_1(t) and c_2(t), set them equal and solve for t. what does this mean exactly?

This should help you a bit, at constant acceleration, call it a, the position of car 2 at time t is at^2/2

the first car, meanwhile is moving at a constant velocity v, so its position at time t is vt

does car 2 start from rest?

so solve vt=at^2/2 -> at^2-vt=0 -> use quadratic formula

this will give you the time t, when car 2 catches up to car 1, ?? to answer part 2 of the Q

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# Homework Help: Acceleration, distance, time. help.

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