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Acceleration Due to Gravity of the Sun

  1. Oct 21, 2007 #1
    1. The problem statement, all variables and given/known data

    What is the acceleration due to gravity of the sun at the distance of the earth's orbit?

    2. Relevant equations

    law of gravity = Gm/r^2
    Sun's Mass: 1.99x10^30 kg,
    earth-sun distance: 150x10^6 km

    3. The attempt at a solution

    ((6.67*10^(-11)) * (1.99*10^30))/ (2.25*10^12)

    = 58992444.4444

    Does this appear correct?
     
  2. jcsd
  3. Oct 21, 2007 #2

    hage567

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    Homework Helper

    Your distance term is not correct. You need to convert it to meters before you square it.
     
  4. Oct 21, 2007 #3
    Out of curiousity...why is r="2.25" where did that come from?
    What are you adding to the mean Earth-Sun distance of 1 AU?

    Casey
     
  5. Oct 21, 2007 #4
    How about this...

    ((6.67*10^(-11)) * (1.99*10^30))/ (2.25*10^22)

    = 0.005899244 m/s^2 ~0.00
     
  6. Oct 21, 2007 #5
    Looks much better. But again, what are you using for a radius?

    Casey
     
  7. Oct 21, 2007 #6
    I'm using the distance from the Earth to the Sun.
    1.50 x 10^11 = r
    r^2 = 2.25*10^22
     
  8. Oct 21, 2007 #7
    Ah. I did not notice that you already squared r. Silly me. Anyway, I do not know what degree of accuracy you are looking for, but you may want to account for the fact that by Newton's Shell Theorem, r would be the distance from the center of one mass to the center of the other.

    Casey
     
  9. Apr 11, 2011 #8
    g=Gm/r^2
    For sun,
    g=6.67*10^-11*1.989*10^30/(695000000)^2
    =274.51m/s

    Isn't it right?
     
  10. Mar 15, 2012 #9
    The earlier posts were almost correct the Sun’s acceleration on the Earth is -
    2pi * Orbital Velocity in (meters/sec ) / Orbital Period (in seconds)
    = 29785.513 * 6.28318531 / 31557600
    = 0.00593036 m/s2
     
  11. Mar 15, 2012 #10
    NB. The Orbital Velocity squared * Radius is a constant for all the planets.
    Eg. OV^2 * R(AU) = approx 887177000

    For the Earth using OV = 29785.52 and R(AU) = 1 then K = 887177201
    For Saturn using OV = 9644.8848 and R(AU) = 9.5371 then K = 887177310
     
  12. May 8, 2012 #11
    without an doubt, the correct answer to the question is from Saladsamurai
    because distance from earth to sun is 1.50x10^8 km or 1.50x10^11m
     
  13. May 11, 2012 #12
    Yes, the distance between sun and Earth is approx 1.5E+11
    Since g = OV^2/R then it still comes out at 0.005914512
    Orbital Velocity squared = 887176784.7
    Check it yourself.

    For a new look at orbits and gravity check out Red Mangon on Facebook.
     
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