Acceleration for a curved trajectory

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The discussion centers on understanding the equation Δv⊥ = vΔθ from Feynman's Lectures on Physics, specifically in section 11-6. Participants express confusion about the equation and its derivation, with some noting the availability of the lectures online for reference. A key point mentioned is the approximation sinΔθ ≈ Δθ when Δθ is small, which is crucial for deriving the result shown in figure 11-8. The conversation highlights the importance of accessing the original material for clarity. Overall, the thread reflects a collaborative effort to grasp complex physics concepts.
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In feynman lectures on physics volume 1
Excerpt 11-6
I don't get how the equation \begin{equation*} \Delta v_\perp=v\,\Delta\theta \end{equation*} is found.
 
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Me neither, I don't have a copy of the Feynman lectures and don't have a clou what this all means.
 
haushofer said:
Me neither, I don't have a copy of the Feynman lectures and don't have a clou what this all means.
They are available online.
 
It would be helpful to link, at least to section 11-6 even if you can't link to the equation: http://www.feynmanlectures.caltech.edu/I_11.html#Ch11-S6

##\sin\Delta\theta\simeq\Delta\theta## if ##\Delta\theta<<1##, is the relevant fact, I think. Then the result follows from figure 11-8.
 
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