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Acceleration of a car when given torque and mass

  1. Jun 14, 2012 #1
    A car has a mass of 1200kg and delivers a total of 2300Nm of torque.
    Tyre radius of 0.306m.
    What is the acceleration of the car in m/s^2?
    What is the speed of the car if it has accelerated for 11 seconds? (determained in first question),


    I have looked at a few and still a bit stuck.
    A=m*R
    and then convert to m/s^2
    or
    W=(fcos theta)(d)

    Attepted both and seem to still be getting the wrong answer..
    A= 1200*0.306
    = 367.2m/s^2

    or
    W=(2300cos45)(0.306*2)
    = (1626.35)(0.612)
    = 995.3262

    As you can see i am well off the right answer. I am more incline to think it is the equation A=m*R...
    Please help!!
     
  2. jcsd
  3. Jun 15, 2012 #2
    lofty28,

    How many newtons of force are applied to the auto when when 2300n-m of torque are applied to a tire of 0.306m radius?

    Ratch
     
  4. Jun 15, 2012 #3
    Newtons of force.... Would that be the mass...? soo 1200kg or 11767.98 N.
    Is this what you mean?
     
  5. Jun 15, 2012 #4
    lofty28,

    In the MKS system, force is measured in newtons, mass is measured in kilograms.

    Ratch
     
  6. Jun 15, 2012 #5
    All the information given in the question is what i posted before...
    Is there any way that i can figure this out with the given information..?
    Please help i am extremely stuck...

    Thanks
     
  7. Jun 15, 2012 #6
    lofty28,

    Do you know what torque is?

    Ratch
     
  8. Jun 15, 2012 #7
    I have the understand torque is the mesument of power around a pivot point...
    I am not entirly sure, this is proberbly why i am haveing trouble with the question..
     
  9. Jun 16, 2012 #8
    lofty28,

    You need to read a good physics book and find out what torque really is. Then the answer to my question in post #2 will become clear.

    Ratch
     
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