1. The problem statement, all variables and given/known data A mass of 0.5 kg is suspended from a flywheel as shown in FIGURE 2. If the mass is released from rest and falls a distance of 0.5 m in 1.5 s. Mass of wheel: 3kg Outside rad. of gyration of wheel: 300mm Radius of gyration: 212mm calculate: (a) The linear acceleration of the mass. (b) The angular acceleration of the wheel. (c) The tension in the rope. (d) The frictional torque, resisting motion 2. Relevant equations a = u t + 2s / t^2 alpha = a / r 3. The attempt at a solution a. a = u t + 2s / t^2 = 0.444 m s^-2 b. alpha = a r = 0.444 / 0.3 = 1.48 rad s^-2 c. Now I have found online that this is T = m (g - a) However neither my learning materials or the online answers I have found offer an explanation of this, other than it being derived from the second law F = m a. Any explanation on this would be appreciated, as I am not willing to use an answer I do not understand. d. I am yet to try this one so am not yet looking for help, no doubt I will need it soon. I am aware these have been answered elsewhere before, but as I said I am looking to understand c. specifically.