- #1

tom_m132

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## Homework Statement

A mass of 0.5 kg is suspended from a flywheel as shown in FIGURE 2.

If the mass is released from rest and falls a distance of 0.5 m in 1.5 s.

Mass of wheel: 3kg

Outside rad. of gyration of wheel: 300mm

Radius of gyration: 212mm

calculate:

(a) The linear acceleration of the mass.

(b) The angular acceleration of the wheel.

(c) The tension in the rope.

(d) The frictional torque, resisting motion

## Homework Equations

a = u t + 2s / t^2

alpha = a / r

## The Attempt at a Solution

a. a = u t + 2s / t^2

= 0.444 m s^-2

b. alpha = a r

= 0.444 / 0.3

= 1.48 rad s^-2

c. Now I have found online that this is T = m (g - a) However neither my learning materials or the online answers I have found offer an explanation of this, other than it being derived from the second law F = m a. Any explanation on this would be appreciated, as I am not willing to use an answer I do not understand.

d. I am yet to try this one so am not yet looking for help, no doubt I will need it soon.

I am aware these have been answered elsewhere before, but as I said I am looking to understand c. specifically.[/B]