Acceleration of a car when given torque and mass

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Discussion Overview

The discussion revolves around calculating the acceleration of a car given its torque, mass, and tire radius. Participants explore the relationships between torque, force, and acceleration, as well as the application of relevant equations in this context.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant presents a problem involving a car's mass, torque, and tire radius, seeking to find acceleration and speed after a certain time.
  • Another participant questions how to convert torque into force applied to the tires, suggesting a need to clarify the relationship between torque and force.
  • There is confusion about the definition of force, with one participant equating mass to force, indicating a misunderstanding of the concepts involved.
  • Participants discuss the importance of understanding torque as a measure of rotational force around a pivot point, which is crucial for solving the problem.
  • One participant expresses frustration over not being able to solve the problem despite attempting various equations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to approach the problem, and there are evident misunderstandings regarding the concepts of torque and force. The discussion remains unresolved as participants continue to seek clarification.

Contextual Notes

There are limitations in the understanding of fundamental physics concepts such as torque and force, which may affect the ability to solve the problem accurately. The discussion reflects a need for foundational knowledge in mechanics.

lofty28
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A car has a mass of 1200kg and delivers a total of 2300Nm of torque.
Tyre radius of 0.306m.
What is the acceleration of the car in m/s^2?
What is the speed of the car if it has accelerated for 11 seconds? (determained in first question),


I have looked at a few and still a bit stuck.
A=m*R
and then convert to m/s^2
or
W=(fcos theta)(d)

Attepted both and seem to still be getting the wrong answer..
A= 1200*0.306
= 367.2m/s^2

or
W=(2300cos45)(0.306*2)
= (1626.35)(0.612)
= 995.3262

As you can see i am well off the right answer. I am more incline to think it is the equation A=m*R...
Please help!
 
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lofty28,

How many Newtons of force are applied to the auto when when 2300n-m of torque are applied to a tire of 0.306m radius?

Ratch
 
Newtons of force... Would that be the mass...? soo 1200kg or 11767.98 N.
Is this what you mean?
 
lofty28,

Newtons of force... Would that be the mass...? soo 1200kg or 11767.98 N.
Is this what you mean?

In the MKS system, force is measured in Newtons, mass is measured in kilograms.

Ratch
 
All the information given in the question is what i posted before...
Is there any way that i can figure this out with the given information..?
Please help i am extremely stuck...

Thanks
 
lofty28,

Do you know what torque is?

Ratch
 
I have the understand torque is the mesument of power around a pivot point...
I am not entirly sure, this is proberbly why i am haveing trouble with the question..
 
lofty28,

You need to read a good physics book and find out what torque really is. Then the answer to my question in post #2 will become clear.

Ratch
 

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