Acceleration of block down an incline

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SUMMARY

The acceleration of block A moving downward on an incline at a 40-degree angle can be calculated using the forces acting on it. The weight of block A is 103N, and the tension in the system is 31N. The normal force is determined by the equation mgcos40, while the frictional force is calculated using the kinetic coefficient of 0.25. The net force equation, Fnet = (31 + 103sin40 * 0.25) - 103cos40, is essential for deriving the acceleration of block A.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with friction coefficients (static and kinetic)
  • Ability to resolve forces into components
NEXT STEPS
  • Study the derivation of net force equations in inclined plane problems
  • Learn about the effects of static and kinetic friction on motion
  • Explore advanced applications of Newton's laws in dynamics
  • Investigate the role of tension in pulley systems and inclined planes
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to explain concepts of forces on inclined planes.

aliaze1
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Homework Statement


06_38.gif


Find the acceleration of block A when moving downward

Theta=40 degrees
A=103N
B=31N
Static coefficient = 0.56
Kinetic coefficient = 0.25

Homework Equations



F=ma
Normal Force * Kinetic coefficient = Friction Force

The Attempt at a Solution



From 103/9.8 I get a mass of ~10.5

Breaking 103 into components, 103sin40 and 103cos40, the first being perpendicular and the second being along the plane

103sin40*0.25=Friction Force

Tension is 31, so the sum of forces is:

(31+103sin40*0.25)-103cos40 = Fnet

Fnet/10.5 = Acceleration of A

is this correct?

Thanks!
 
Last edited:
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you have mixed up the normal force and the force going down the ramp

mgcos40 would be the FN ; use this to find the frictional force
mgsin40 would be the force with which it accelerates down the ramp

try writing some net force equations ; those would help :]
 

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