- #1

- 476

- 30

- Homework Statement
- 2 masses on each side of the inclined plane. Coefficient of kinetic friction = 0.3, held by an inextensible string.

Masses of blocks as labelled on the diagram

- Relevant Equations
- -

So I figured out the equation, but it is probably wrong because the answer doesn't tally.

Since the string is inextensible, I can assume that tension is the same for both sides, and acceleration for both masses is the same too So:

I can say that the acceleration of 2kg block =acceleration of 7kg block

$$\dfrac {7g\sin 40-T}{2+7}=\dfrac {T+\left( 0.3\right) \left( 2g\cos 50\right) -2g\sin 50}{7+2} $$

I got T = 29.36N, and used one of the equation to get my acceleration. However, it seems to be wrong :/

Is there something wrong with my equation? Thanks