Acceleration only due to conservation of angular momentum

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The discussion centers on the relationship between conservation of angular momentum and acceleration in planetary motion. It explains that while angular momentum remains constant, the absence of a force in the tangential direction (\hat{\boldsymbol{\theta}}) implies no direct acceleration in that direction. However, as the radius (r) decreases, the tangential velocity (v_{\theta}) must increase to maintain constant angular momentum. This leads to a perceived contradiction, as acceleration typically requires a force. The conclusion drawn is that the change in speed occurs due to the non-perpendicular nature of the gravitational force relative to the velocity when the distance changes.
Soren4
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I don't understand why the conservation of angular momentum can imply an acceleration, in absence of a force.

Consider for istance planetary motion. The angular momentum \vec{L} of the planets is conserved and that means \mid \vec{L} \mid=mr^2 \dot{\theta}=mrv_{\theta} is conserved too.

Consider the acceleration in polar coordinates
$$
\left( \ddot r - r\dot\theta^2 \right) \hat{\mathbf r} + \left( r\ddot\theta+ 2\dot r \dot\theta\right) \hat{\boldsymbol{\theta}} \ $$

The second term is zero since \vec{L} is constant. In fact the second term can be rewritten as <br /> a_{\theta}=\frac{1}{r}[\frac{d}{dt}(r^2 \dot{\theta})]=\frac{1}{r}[\frac{d}{dt}(\frac{L}{m})].
This means that there is no acceleration in the direction of \hat{\boldsymbol{\theta}}, which is clear since the gravitational force is a central froce.

But if the distance r decreases v_{\theta} (i.e. the velocity in the direction of \hat{\boldsymbol{\theta}}) must increase in order to keep \mid\vec{L} \mid constant.

How can v_{\theta} increase if there is no acceleration in the direction of \hat{\boldsymbol{\theta}}?

I understood that it happens because of the conservation of angular momentum but if there is an acceleration, necessarily a force is needed. I don't see where do this force come from.
 
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Speed changes because the force is not perpedicular to velocity, when the distance changess.
 

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