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Acceleration overcoming Velocity. Over what time frame?

  1. Sep 13, 2012 #1
    1. The problem statement, all variables and given/known data
    A particle leaves its initial position Xo at time t=0, moving in the positive x direction with speed Vo but undergoing acceleration a in the negative x-direction. Find expression for (a) the time when it returns to Xo and (b) its speed when it passes that point



    I'm having difficulting finding my second time t2. If I have this I can find the speed with V=(X-Xo)/(t-0). I'm trying to get into this course but am drawing a blank at this time. If someone could give me a few words in an explanation, I'd be greatly appreciative. It may just open my eyes.

    Mike
     
  2. jcsd
  3. Sep 13, 2012 #2
    You can't get speed with V=(X-Xo)/(t-0). The speed is not constant, there is acceleration. How does speed depend on time under constant acceleration?
     
  4. Sep 14, 2012 #3

    vela

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    What have you tried to find t2?
     
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