Acceleration, screwed up vector?

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    Acceleration Vector
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Homework Help Overview

The discussion revolves around understanding acceleration in the context of a free-falling body problem involving a diver. The original poster seeks clarification on when acceleration is considered negative, particularly in relation to direction and deceleration.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the conditions under which acceleration is negative, especially when an object is slowing down versus its direction of motion. They explore the implications of their coordinate system choice on the signs of velocity and acceleration.

Discussion Status

Some participants have offered insights into the relationship between acceleration and the chosen coordinate system, noting that acceleration can be negative when it opposes the direction of motion. The conversation has prompted further exploration of these concepts, with participants engaging in clarifying the definitions and implications of acceleration.

Contextual Notes

The original poster references specific values and equations related to the diver's motion, indicating a structured approach to solving the problem while grappling with the underlying concepts of acceleration and direction.

kholdstare121
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acceleration: screwed up vector??

I need things cleared up when it comes to acceleration.
Is acceleration negative when it points in a certain direction...or when an object is slowing down?
I was working on a free falling bodies word problem:
A diver springs upward with an initial speed of 1.8 m/s from a 3.0-m board.
(a) find the velocity with which he strikes the water.[Hint: when the diver reaches the water, his displacement is y=-3.0 meters (measured from the board), assuming that the downward direction is chosen as the negative direction.]
(b) What is the highest point he reaches above the water?
I can get the final velocity from part (a) alright,
To find the distance he jumps up, if I use a positive acceleration in the equation:
Vf^2=Vi^2+2ad
then I get a negative distance...which I shouldn't if he's traveling UPWARD as he jumps.
I use the same equation to get the final velocity as he hits the water:
Vf^2=vi^2+2ad
and I used both a negative displacement vector(-3.17m) and a negative acceleration vector(-9.8 m/s^2) and got + or - 7.9 m/s as the answer(I used the minus one, and it was the right answer)
but my question is: when is acceleration negative?
Thanks :smile:
 
Last edited:
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Actually nevermind!
I did some research and found out that if an object is going in the positive direction and Deccelerating, then the sign of the acceleration is opposite of the direction.
I think that's right?
 
The answer is actually right there in your post. You choose a coordinate system. The direction of the kinematic quantities are then either positive or negative with respect to the chosen coordinate system.

It is true though that a deceleration means that the acceleration of the object is in the opposite direction of the motion of the object though. So if the object is moving in the negative direction (its velocity then being negative, but its position can be positive or negative), then its acceleration (or deceleration) will then be positive.

kholdstare121 said:
I need things cleared up when it comes to acceleration...

A diver springs upward with an initial speed of 1.8 m/s from a 3.0-m board.
(a) find the velocity with which he strikes the water.[Hint: when the diver reaches the water, his displacement is y=-3.0 meters (measured from the board), assuming that the downward direction is chosen as the negative direction.]

Thanks :smile:


Hope I have'nt confused you even more! If so keep the thread going!
 
Yeah, I got through my physics h.w. much easier after having that cleared up.
thanks
 

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