Action of Lie Brackets on vector fields multiplied by functions

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SUMMARY

The discussion centers on the application of the Lie bracket, specifically the product rule when one vector field is multiplied by a function. The expression discussed is [fX + Z, Y] = f[X, Y] + [Z, Y] - (Yf)Xg. The third term, -(Yf)Xg, arises from the derivation properties of vector fields acting on smooth functions. Understanding this product rule is essential for mastering Lie brackets in differential geometry.

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  • Understanding of Lie brackets and commutators in vector fields
  • Familiarity with smooth functions and their derivatives
  • Basic knowledge of differential geometry concepts
  • Experience with vector calculus and operations on vector fields
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  • Learn about derivations and their application to smooth functions
  • Explore examples of vector fields and their interactions
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Students and researchers in differential geometry, mathematicians focusing on vector fields, and anyone seeking to deepen their understanding of Lie brackets and their applications in mathematical physics.

tut_einstein
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Hi,

Is there a specific product rule or something one must follow when applying the lie bracket/ commutator to two vector fields such that one of them is multiplied by a function and added to another vector field? This is the expression given in my textbook but I don't see how:

[fX+Z,Y] = f[X,Y] + [Z,Y] - (Yf)Xg

I don't see where the third term on the right hand side comes from.

I'd really appreciate some help on this because I'm self-learning differential geometry for a research project and almost all my doubts revolve around my not understanding how lie brackets work. So any help will be appreciated.

Thanks!
 
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tut_einstein said:
Is there a specific product rule or something one must follow when applying the lie bracket/ commutator to two vector fields such that one of them is multiplied by a function

Yes.
tut_einstein said:
This is the expression given in my textbook

Which book?

Let's go back a couple of steps.

If X is a vector field and f and g are smooth functions, then both Xf and Xg are functions. Because f and g are both functions, the product fg is also a function on which X can act. Consquently, X \left(fg\right) is a function. X acts like a derivative (is a derivation) on the set (ring) of smooth functions, i.e.,
X \left(fg\right) = g Xf + f Xg.
Now, use the above and expand
\left[ fX,Y \right]g .
 
Last edited:

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