Adding heat for final temperature

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Homework Help Overview

The problem involves calculating the heat required to raise the temperature of a specified mass of water and subsequently determining the final temperature of an equal mass of mercury when the same amount of heat is applied. The subject area pertains to thermodynamics and heat transfer.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of heat using the formula Q=c*M*(t2-t1) and question the specific heat value used for water. There is confusion regarding the units and the resulting calculations, particularly the discrepancy in the calculated heat value.

Discussion Status

Some participants have offered guidance on the specific heat of water and the need for unit consistency. There is an ongoing exploration of the correct values and methods to use, with no clear consensus reached yet.

Contextual Notes

Participants note potential issues with unit conversions and the specific heat values being used, indicating a need for clarity on whether calculations are in calories or joules.

shakejuhn
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Homework Statement


How much heat is required to raise the temperature of 0.250kg of water from 20.0oC to 30.0oC?

If this amount of heat is added to an equal mass of mercury that is initially at 20.0oC, what is its final temperature?


Homework Equations



Q=c*M*(t2-t1)

The Attempt at a Solution



for the first part i got
q=1*0.250*(30.0-20.0)
q=10.4725
this is wrong the correct answer was 1.05*10^4
how did they get that answer?

The second part i have so far
1.05*10^4=c*0.250*(t2-20)
it didnt say what the spefice heat of mercury was so i looked it up and it was 0.140
1.05*10^4=0.140*0.250*(t2-20)
1.05*10^4/(.035)+20

please help with this
 
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For the first part why are you using 1 for c? Look up the specific heat of water. Regardless, I don't see how you got 10.4725 from your equation for q. Is there a typo in there somewhere?
 
shakejuhn said:

Homework Statement


How much heat is required to raise the temperature of 0.250kg of water from 20.0oC to 30.0oC?

If this amount of heat is added to an equal mass of mercury that is initially at 20.0oC, what is its final temperature?


Homework Equations



Q=c*M*(t2-t1)

The Attempt at a Solution



for the first part i got
q=1*0.250*(30.0-20.0)
q=10.4725
this is wrong the correct answer was 1.05*10^4
how did they get that answer?

The second part i have so far
1.05*10^4=c*0.250*(t2-20)
it didnt say what the spefice heat of mercury was so i looked it up and it was 0.140
1.05*10^4=0.140*0.250*(t2-20)
1.05*10^4/(.035)+20

please help with this

You have to be clear on your units. You appear to be working in calories and kg. If so, you have to use a specific heat for water in calories/kg deg not calories/g deg.

AM
 
i just said find the answer in joules
 
shakejuhn said:
i just said find the answer in joules
If you are using a specific heat of 1 for water you are working in calories/g. Kelvin. If you want the answer in joules you have to multiply the answer by 4.186 (ie. 4.186 J in one cal.). The specific heat for water in Joules/Kg K is 4186.

AM
 
Last edited:

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