Final temperature for two blocks of iron placed in contact

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Homework Help Overview

The problem involves two blocks of iron with different initial temperatures placed in contact, and the goal is to determine the final temperature when no heat is exchanged with the surroundings. The subject area pertains to thermodynamics and heat transfer principles.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the heat exchange between the two blocks, with one attempting to set up an equation based on heat gained and lost. Questions arise regarding the signs in the equations and the assumptions made about heat transfer.

Discussion Status

Some participants have provided guidance on setting up the equations correctly, emphasizing the importance of sign conventions in heat transfer. There is an ongoing exploration of the assumptions involved in the problem, particularly regarding the direction of heat flow.

Contextual Notes

There are indications of confusion regarding the setup of the equations and the interpretation of temperature changes, as well as a caution against making assumptions that fit a desired answer.

dwight_v
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Homework Statement



Two blocks of iron, one of mass m at 10.0C and the other of mass 2m at 25.0c, are placed in contact with each other. If no heat is exchanged with the surroundings, which of the following is the final temperature of the two blocks?
A)10
B)15 .
D) 20C ( this is the answer)

The Attempt at a Solution



I tried to solve doing m(x-10) = 2m(x-25) but then I get x = 40. The answer is 20, but I don't see why you would divide x by 2. [/B]
 
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What do you think should happen, can you give a range between where you think the final temperature should lie? Should any of the iron blocks lose heat or gain heat?

Use this to think about the signs.
 
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doggydan42 said:
What do you think should happen, can you give a range between where you think the final temperature should lie? Should any of the iron blocks lose heat or gain heat?

Use this to think about the signs.
ya i think i got it ==> m(x-10) = 2m(25-x) because heat gained = heat lost
 
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Moderator's note: Thread title changed to make it more descriptive of the question being asked.
 
dwight_v said:
ya i think i got it ==> m(x-10) = 2m(25-x) because heat gained = heat lost

I know you figure it out, but I'm going to caution you here because you're making some ad hoc decisions to fit the answer, especially when you reverse the sequence of (25 - x) in your second term.

Follow this rule: ΔT always means Tf - Ti. All you need to do is to write the specific heat equation in just one way:

Q = mc ΔT

In this case, Q = mc(Tf - 10C) + 2mc(Tf - 25C). --- (1)

Now, the simplification here is that (i) Q = 0, since there is no heat loss anywhere, and (ii) c is the same for both. So that equation simplifies to

Tf - 10C + 2Tf - 50C = 0

This gives

3 Tf = 60 C

Thus,

Tf = 20 C.

I did not have to "think" which one loses or gains heat. All I did was set up equation (1), and then I follow the mathematical rule. If I want to know which one gained or lose energy, all I have to do is use the value of Tf that I got, and then look at which of the term in Eq. 1 is positive (heat gained) and which one is negative (heat loss).

The key thing here is that question like this is a TRAP in terms of jumbling up the SIGNS. If you keep the whole equation only to one side of the equation, keeping only "Q" on the other side, you'll never go wrong and you'll never have to insert the sign by hand.

Zz.
 

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