Adding Vectors: Using Angles and Formulas | Vector Addition Explained

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SUMMARY

The discussion focuses on vector addition using the formula for the magnitude of the resultant vector, specifically \(\sqrt{a^2 + b^2 + 2ab \cos \theta}\), where \(\theta\) is the smallest angle between vectors \(a\) and \(b\). Participants explore whether the larger angle can be utilized for this calculation, concluding that using the larger angle does not change the cosine value, as \(\cos(360^\circ - \theta) = \cos(\theta)\). Visualizing vectors head-to-tail is recommended for better understanding of the addition process.

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physics kiddy
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To add two vectors, a\rightarrow and b\rightarrow we use the formula \sqrt{}a2+b2+2abcosθ

where θ is the smallest angle between vectors a and b. Is there any way I can use the bigger angle to calculate the sum ? It's not a homework, just a question from my intution.

I have attached a pic also... Thanks in advance for help
 

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hi physics kiddy! :smile:
physics kiddy said:
Is there any way I can use the bigger angle to calculate the sum ?

you mean 360° - θ ?

but cos(360° - θ) equals cosθ :confused:

btw, the formula is easier to understand if you draw a and b head-to-tail (instead of tail-to-tail) :wink:
 
physics kiddy said:
To add two vectors, a\rightarrow and b\rightarrow we use the formula \sqrt{}a2+b2+2abcosθ

where θ is the smallest angle between vectors a and b. Is there any way I can use the bigger angle to calculate the sum ? It's not a homework, just a question from my intution.

I have attached a pic also... Thanks in advance for help

To use the bigger angle, all you need to do is to express cos(360-x) in terms of cos(x), which in fact is cos(360-x) = cos(x) :wink:
 

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