Addition of vectors with triangle vertices

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SUMMARY

The discussion focuses on the vector addition of triangle vertices A, B, and C, specifically calculating (A→B) + (B→C) + (C→A). The solution reveals that the sum of these vectors results in the zero vector, confirming that the vectors cancel each other out. The participant initially struggled with the format of the answer but ultimately understood that the result is 0, expressed as 0i + 0j.

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Homework Statement



If A, B, and C are the vertices of a triangle, find the following.
(A→B) + (B→C) + (C→A)


The answer has to be given like this:

_____ i + _____ j

2. Homework Equations (I think?)
a+b=b+a
a+(b+c)=(a+b)+c
a+0=a
a+(-a)=0
c(a+b)=ca+cb
(c+d)a=ca+da
(cd)a=c(da)
1a=a

The Attempt at a Solution



I'm not even sure what kind of solution this should look like. My best guess would be
<A+B+C>i + <A+B+C>j
Any better, more sensible ideas? Thanks!
 
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The vector connecting A to B is given by the vector (B-A), where B and A are the coordinates of the points. Add up all three terms. What do you get?
 
Oh okay, so it all cancels out and comes to 0. That makes sense. Thank you!
 

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