Adiabatic compression of an ideal gas

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Homework Help Overview

The discussion revolves around the adiabatic compression of an ideal gas, specifically focusing on determining the final temperature after compressing the gas from an initial volume of 70.0 L to a final volume of 43.0 L, given a specific heat capacity at constant volume (CV) of 2.50R.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between temperature and volume during adiabatic processes, questioning how to derive the ratio of specific heats (γ) and its implications for the problem. There is uncertainty about how to determine the number of moles (n) and its necessity for solving the problem.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the relationships involved in adiabatic processes. Some guidance has been provided regarding the adiabatic condition and the use of specific heat ratios, but there is still confusion about the role of the number of moles and how to proceed without it.

Contextual Notes

Participants note the lack of pressure information, which complicates the determination of the number of moles (n). There is an emphasis on understanding the relationships between temperature, volume, and the specific heat capacities in the context of the problem.

Rasine
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An ideal gas at a temperature of 17.7°C is compressed adiabatically from an initial volume 70.0 l to a final volume 43.0 l. Find its final temperature (in °C) if CV = 2.50R.


so T1V1^g=T2V2^g


to find g=cp/cv=(cv+nR)/cv and cv=2.50R

g=(2.50R+nR)/2.50R factor out an R g=(2.50+n)/2.50 factor out 2.50

g=n/2.50

but how do i find n...if what i did above is even right
 
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Rasine said:
An ideal gas at a temperature of 17.7°C is compressed adiabatically from an initial volume 70.0 l to a final volume 43.0 l. Find its final temperature (in °C) if CV = 2.50R. so T1V1^g=T2V2^g
It helps to start with the correct relationship. The adiabatic condition is:

[tex]PV^\gamma = K[/tex]

Substitute P = nRT/V to give:

[tex]TV^{\gamma-1} = K/nR = constant[/tex]

You can't determine what n is since you don't have the pressure. But you don't need it to solve the question.

AM
 
Last edited:
so how do i get what i denoted as g
 
do i solve for what ever nR is
 
i am so confused! please give me another hint
 
Rasine said:
i am so confused! please give me another hint
What is [itex]TV^{\gamma-1}[/itex] initially?

Does it change?

So what is it at the end?

You are given the volume at the end. So what is T at the end?

Note: [itex]\gamma = C_p/C_v \text{ and } C_p = C_v + R[/itex]

[itex]\gamma[/itex] is simply a ratio of specific heats so it is dimensionless.

AM
 

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