Adiabatic compression of an ideal gas

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Rasine
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An ideal gas at a temperature of 17.7°C is compressed adiabatically from an initial volume 70.0 l to a final volume 43.0 l. Find its final temperature (in °C) if CV = 2.50R.


so T1V1^g=T2V2^g


to find g=cp/cv=(cv+nR)/cv and cv=2.50R

g=(2.50R+nR)/2.50R factor out an R g=(2.50+n)/2.50 factor out 2.50

g=n/2.50

but how do i find n...if what i did above is even right
 
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Rasine said:
An ideal gas at a temperature of 17.7°C is compressed adiabatically from an initial volume 70.0 l to a final volume 43.0 l. Find its final temperature (in °C) if CV = 2.50R. so T1V1^g=T2V2^g
It helps to start with the correct relationship. The adiabatic condition is:

[tex]PV^\gamma = K[/tex]

Substitute P = nRT/V to give:

[tex]TV^{\gamma-1} = K/nR = constant[/tex]

You can't determine what n is since you don't have the pressure. But you don't need it to solve the question.

AM
 
Last edited:
Rasine said:
i am so confused! please give me another hint
What is [itex]TV^{\gamma-1}[/itex] initially?

Does it change?

So what is it at the end?

You are given the volume at the end. So what is T at the end?

Note: [itex]\gamma = C_p/C_v \text{ and } C_p = C_v + R[/itex]

[itex]\gamma[/itex] is simply a ratio of specific heats so it is dimensionless.

AM