Adiabatic expansion of infinite square well

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SUMMARY

The discussion focuses on the adiabatic expansion of an infinite square well, specifically when the right wall expands from width L to 2L. The geometric phase was calculated and determined to be zero after integrating the wave function with respect to the wall's expansion. The dynamic phase, however, remains unresolved due to complications arising from the non-constant rate of expansion, leading to a dynamic phase expression involving the integral of 1/(L+v(t)*t)², where v(t) represents the velocity of the expansion.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly wave functions and phases.
  • Familiarity with the concept of adiabatic processes in quantum systems.
  • Knowledge of integration techniques in calculus, especially in relation to variable limits.
  • Proficiency in the mathematical representation of energy levels in quantum wells, specifically En=n²π²ħ²/(2mL²).
NEXT STEPS
  • Research the implications of non-adiabatic transitions in quantum mechanics.
  • Study advanced integration techniques for variable limits in calculus.
  • Explore the concept of geometric and dynamic phases in quantum systems.
  • Investigate the effects of boundary changes on quantum states and energy levels.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying wave functions, adiabatic processes, and the behavior of quantum systems under varying boundary conditions.

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Homework Statement



Suppose that an infinite square well has width L , 0<x<L. Nowthe right wall expands slowly to 2L. Calculate the geometric phase and the dynamic phase for the wave function at the end of this adiabatic expansion of the well. Note: the expansion of the well does not occur at a constant rate.

Homework Equations



Dynamic phase= -1/ħ * ∫ En(t') dt' from 0 to t
Geometric phase= i * ∫ <ψn,∂t'ψn>dt' from 0 to t

The Attempt at a Solution


First, I calculated the geometric phase by getting the wave function in terms of L and integrating the bra and ket with dL instead of dt. ∂ψ/∂t = ∂ψ/∂L * dL/dt then plugging that in for the geometric phase.

After using the equation for the wave function of the well and some fun integrations the answer for the geometric phase comes out to zero.

However, I am stuck on the dynamic phase.

The energy for a given n is En=n222/(2m*L2)

However, if the expansion doesn't occur at a constant rate the dynamic phase is:

constants*∫ 1/(L+v(t)*t)2 where v(t) is the velocity of the expansion. I'm just not sure how to integrate that to get the dynamic phase.
 
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This problem occurs every now and then. Nevertheless I find it quite dubious. The change of the boundary will mix in states of infinite energy, so you can't do it so slowly that this effect becomes negligible. There is no proper adiabatic limit.
 

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