Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Variable of integration in geometric phase calculation

  1. Nov 22, 2017 #1
    1. The problem statement, all variables and given/known data
    Calculate the geometric phase change when the infinite square well expands adiabatically from width w1 to w2.

    2. Relevant equations
    Geometric phase:
    [tex] \gamma_n(t) = i \int_{R_i}^{R_f} \Bigg< \psi_n \Bigg | \frac{\partial \psi_n}{\partial R} \Bigg > dR [/tex]

    Infinite square well wave function:
    [tex] \psi_n = \sqrt{\frac{2}{w}}sin \Big(\frac{n \pi x}{w}\Big) [/tex]

    3. The attempt at a solution
    This is an adiabatic approximation problem, and the variable R(t) here is the width of the well, w.
    I took a derivative of the wave function and am integrating a dot product of the wave function with its derivative over w.

    [tex] \gamma_i (t) = i \int_{w_1}^{w_2} \Big(-\frac{1}{2 w^2}\Big) sin^2 \Big(\frac{n \pi x}{w}\Big) dw - 2 i \int_{w_1}^{w_2} \frac{n \pi x}{w^3} sin\Big(\frac{n \pi x}{w}\Big) cos\Big(\frac{n \pi x}{w}\Big) dw[/tex]

    The first element appears to be unintegrable. I have looked at the solutions to this problem done by other people, and the integration is done over dx instead of dw, which clearly alleviates the integration problem above. Why is it valid to integrate over dx, even though the geometric phase formula above indicates integration over R, i.e. w?
  2. jcsd
  3. Nov 22, 2017 #2


    User Avatar
    Homework Helper
    Gold Member
    2017 Award

    Note that there are two integrations involved in ##\gamma_n(t) = i \int_{R_i}^{R_f} \left< \psi_n \Bigg | \frac{\partial \psi_n}{\partial R} \right > dR##. In addition to the integration with respect to R, the bra-ket ##\left< \psi_n \Bigg | \frac{\partial \psi_n}{\partial R} \right >## implies an additional integration (over what variable?).
    There is a nice way to deduce the value of ##\int_{R_i}^{R_f} \left< \psi_n \Bigg | \frac{\partial \psi_n}{\partial R} \right> dR ## using just the fact that the wave functions ##\psi_n## are real and normalized. The trick is to relate ##\left< \psi_n \Bigg | \frac{\partial \psi_n}{\partial R} \right>## to ##\frac{\partial }{\partial R}\left< \psi_n | \psi_n\right>## .
    Last edited: Nov 22, 2017
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted