- #1

Apashanka

- 429

- 15

For this problem at t=0

Ψ(x,0)=Ψ

_{1}-Ψ

_{3}

Where Ψ

_{1}and Ψ

_{3}are the normalised eigenstates corresponding to energy level 1 and 3 of the infinite square well potential.

Now for it's time evolution it will be Ψ

_{1}exp(-iE

_{1}t/ħ)- Ψ

_{3}exp(-iE

_{3}t/ħ)

And taking the time given in the question the time part of the individual states is coming to be exp(-iπ/8) and exp(-9iπ/8) respectively which is equivalent to (-1)^(-1/8) and (-1)^(-9/8) respectively and the two are equal

Hence in my opinion the ans is option 3

But the correct option is given option 4??

Am I right?