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Adjust supply voltage based on divider resistance

  1. Feb 12, 2016 #1
    Hello, I'm working on a project and I need some assistance. I need to adjust the negative supply voltage to an integrator opamp that I use for DC offset control based upon the resistance in a voltage divider elsewhere in the design.
    Draft24-2.png
    R12 is the trimmer resistor to adjust the CVS circuit and V5 is the power supply that I need to adjust based upon the resistance of R12. So I need some sort of mechanism that will measure the resistance of R12 and then increase the power supply voltage as the resistance of R12 decreases. I need amount of adjustment to be adjustable as well.
    Any ideas?
     
  2. jcsd
  3. Feb 12, 2016 #2

    CWatters

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    Perhaps use a dual gang pot for R12. Eg as used for the volume control on some stereo amplifiers.
     
  4. Feb 12, 2016 #3
    Unfortunately R12 must be an opto-isolator because the circuit will be digitally controlled.
     
  5. Feb 12, 2016 #4

    jim hardy

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    A question well stated.. (something has to be pretty true to achieve platitude status)....

    okay , i see R12 with his wiper position controlled by "Mr servo" .

    Is R12 a potentiometer or a rheostat ?
    We don't know much about "load" ?
    Where is that "null output" you're trying to achieve measured ?

    To the question as i read it -
    If a rheostat, R11 and R12 form a half-bridge
    differencing amplifiers might report voltage across each , they might be ratio'ed

    or an R11B and R12B string connected from V6 to load would give you a whole bridge whose unbalance you could difference-ampify ,
     
  6. Feb 12, 2016 #5
    Actually in the audio circles a servo refers to anything that changes something based on another change in something. The "servo" is the device I'm trying to make.
    It's an LDR so technically it's more like a potentiometer.
    Not shown in this schematic. A change in operating point in the stage (done by the CVS) requires adjustment to the DC offset "servo" in order to maintain the null.
     
  7. Feb 12, 2016 #6
    You might try adding a current mirror to isolate the current through the resistor. Then with the voltage and the current... Not an elegant solution.

    Yet since R12 is controlled, perhaps you can estimate it from the control current? This may lead to a more elegant design.
     
  8. Feb 12, 2016 #7
    Yeah that may end up being the solution, I'll have to use a digital control and offset. The problem then is how do I adjust the power supply. Maybe a depletion mode mosfet or something, I don't think opto-isolators work with negative voltage..
     
    Last edited: Feb 12, 2016
  9. Feb 12, 2016 #8

    jim hardy

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    LDR? Light Dependent Resistor?

    I'm old fashioned
    to me a two terminal variable resistor is a "rheostat"
    a three terminal variable resistor is a "potentiometer"

    though the terms really apply more to how they're connected than how they're built

    00343x01.png

    upload_2016-2-12_16-59-52.png

    potentiometer vs rheostat connections - mnemonic for me is
    potentio- , implying potential difference or voltage + meter = measure , as with a Wheatstone bridge
    and rheo = flowing, + stat = control, as with a series resistor to control current flow

    All that aside - thanks for the clarification.

    draft24-2-png.95710.png


    Not knowing anything about load,

    Looks like current through R11 and R12 hovers around a few tens of microamps to bias PMOS on ?( a few volts across R11)
    so decreasing R12 would turn on PMOS harder, turning on Q3, dumping more current to Load, increasing Vload to restore constant current through R11&R12...

    Looks to me like Vload then is a rough measure of R12
    well maybe an inverse measure

    if this is inside a closed loop might you get away with something so crude ?

    Just a thought.

    old jim
     
    Last edited: Feb 12, 2016
  10. Feb 12, 2016 #9
    This is the description of the circuit
    CS-Load-Servo-Wavebourn.gif
    So in essence It's a CVS triode load, at least that's what I take from it.
     
  11. Feb 12, 2016 #10

    jim hardy

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    now current exiting R2 can split to Q1 unlike when Q1 was a FET...

    is R3 still servo controlled ?

    moving target here

    time to try an experiment i'd say. Are you building this or simulating it ?
     
  12. Feb 12, 2016 #11

    meBigGuy

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    Referencing the original picture:
    I'd like to help, but I'll be darned if I can figure out what you are really trying to do (never figured out the previous thread either). What is U3 doing? It's an integrator, running open loop at DC, and saturates at the negative or positive supply depending on the input. What does changing the negative supply do for you? Doesn't change anything if you are not saturated.

    You want the adjustment to the negative supply to depend on the value of R12 independent of the components around it? You are controlling it digitally based on what? Can you use the digital input to affect the supply?

    You are leaving something out that I'm not able to assume. I'm lost (and that's usually pretty hard to to).
     
  13. Feb 12, 2016 #12
    It was highly recommended on this thread to make Q1 a fet http://www.diyaudio.com/forums/tubes-valves/140699-anti-triode-sepp-how-do-best.html
    Both, haven't gotten to the build phase yet. In the simulation, the operating point shifts with the AC signal amplitude unlike a normal gyrator load, I have to look into that. Worst case scenario I revert to a normal gyrator load, at the end of the day I just need to be able to adjust the voltage and maintain the current.
    I'm trying to have digitally adjustable load line operating points. I'm using a CCS on the cathode and a CVS on the anode.

    Adjusting the negative supply adjusts the voltage output for the DC offset. Its purpose is to maintain DC null at the output of the stage.
    Draft24-1.png
    For example, if I push a 6080 tube to 250v anode voltage I'll need -150v grid voltage for a proper bias.
    As I decrease the value of R12 I increase the anode voltage which then requires me to increase the supply voltage to U3 in order to have an increased bias voltage.
     
  14. Feb 12, 2016 #13

    jim hardy

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    6080 ??? Low mu triode?

    Are you trying to build a transformerless tube amp ?

    I remain firmly convinced the inductance of the output transformer is necessary for that "warm tube" effect
    and inverting triodes has to be hard on the grid.

    i like low hum low distortion , 7199/6973

    I hope you'll let us know how it sounds
    old jim
     
  15. Feb 12, 2016 #14
    I'm not really interested in the warm tube effect, I'm more interested in realism, this topology offers that in spades at least in my experience.
     
    Last edited: Feb 12, 2016
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